7(x^2+4x)=0

Solution for 7(x^2+4x)=0 equation:

7(x^2+4x)=0

We multiply parentheses

7x^2+28x=0

a = 7; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·7·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*7}=\frac{-56}{14}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*7}=\frac{0}{14}
=0
$